3.Four capacitors connected in series all with the same rating of 15 Mfd. But each has a different voltage rating as following #1 220V #2 440Volts #3 550V #4 360V. Find the total capacitance as well as the total allowable applied voltage
Et = E1 + E2 + E3 + E4
Et = 220 + 440 + 550V + 360
Et = 1570V
1/CT = (1/C1) + (1/C2) + (1/C3)+ (1/C4)
CT = 1/ (1/15) + (1/15) + (1/15)+ (1/15)
CT = 3.75 mfd
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