Design
Steps |
1. |
Load Estimating
-Cooling
-Heating |
2. |
Air System Design |
3. |
Equipment Selection |
4. |
Supporting System |
Each piece of equipment from the design stage through the selection and installation should be maximized to give the customer the most economical and efficient system you can for every dollar he has invested
Step#1: Load Estimating
-Cooling
-Heating
-2 Methods of estimating
-Block load
-Room by room
Accuracy: Blessing or Curse
| Rough Load Estimating |
Benefits |
Disadvantages |
-Fast |
-Liability Maximized |
-Little Paperwork |
-Over Sized |
-Bid More Jobs |
-Bad Reputation |
-Missed Sales |
-Call Backs/ Missed Profits |
-Can't Guarantee Performance |
| Accurate Load Estimating |
Benefits |
Disadvantages |
-Time Consuming |
-Liability Minimized |
-More Skill Required |
-Properly Sized |
-More Paperwork |
-Underbid Competitor |
-Bid Fewer Jobs |
-Professional Estimate |
-Good Reputation |
-Insure Profitability |
-Guarantee System |
-Increase Sales/ Customer Base |
Estimating The Air Conditioning Load
Survey the Structure: To determine the best method of installing the system
Building Orientation:
-Relationship to the sun
-Wind direction
-Location in relation to the other buildings
-Surrounding trees
Building Size: For conduction and convection gains or losses
Building Shape: For air distribution and lay out of duct system
Construction Materials:
-Wall
-Roof
-Floors
Glass Area:
-Percentage (%)
-Type
-Affecting factors
Infiltration + Exfiltration:
-Air coming inside + air going outside
-Door location
-Door construction
-Number of doors
People Occupancy
Equipment Located With In The Structure
Ventilation Requirement
Equipment Location
Utility Services
Building Codes
Principals Of Load Estimating For Air Conditioning Systems
Heat sources for air conditioning load calculations
Inside Conditioned Space
-People
-Appliances
-Lighting
Outside Conditioned Space
-Transmission gains
-Walls
-Roof
-Solar Gains
-Windows
Additional Loads
-Ceilings
-Floors
-Infiltration gains
-Cracks in building envelope
Outside Heat Sources (Transmission Gains)
-Walls/ Roof
-Affected by materials used in construction/ the total area of the surface/ solar effects as well as the temp diff. across the material
To Determine the amount of heat transfer thru the buildings surfaces (by conduction) the following formula is used.
BTU's/hr = |
(Overall co-efficient of heat transfer) |
X (Surface Area) |
X TD (U-Factor) |
How To Reduce Conduction Gains Through Walls + Roofs
1. Additional Insulation In Walls/ Roofs |
Insulation |
%reduction in heat flow |
1 |
48 to 55% |
2 |
62 to 68% |
3 |
70 to 74% |
4 |
72 to 78% |
It should be noted that any increase beyond 4 will not significantly improve overall U-Factor of structure
2. Roof Materials
Light Construction Wooded frame (18 BTU's sq ft) max no insulation
Medium Construction 4 Concrete (19 BTU's sq ft) max no insulation
Heavy Construction 6 Concrete (15 BTU's sq ft) max no insulation
The above info is taken at peak solar gain times, approx. 3:00 pm. in the afternoon
Solar gains can be reduced by two methods:
-Shaded roof = reduction by 75%
-Roof sprays = reduction of 65%
U Factors for typical construction types
-Residential wall = 0.25
-Residential roof = 0.31
-Commercial wall = 0.33
-Commercial roof = 0.40
Transmission Gain Calculation
-Find the total heat gain through a residential wall with the following dimensions.
-Length = 20'
-Height = 8'
-Outside ambient temp 85ºF
-Inside room temp 75ºF
Heat Gain = |
Area x |
TD x |
U-Factor |
400 BTU/H= |
(20x8)160 x |
10 x |
0.25 |
Outside Heat Sources (Solar + Conduction Gains)
Windows
The Solar heat entering a structure through glass is immediately absorbed in the room. The amount of solar gain through the windows is determined by the TD surface area and type of glass used in its construction. Conduction gains through glass will also use the same formula
To determine the amount of heat gain (solar as well as conduction) the following formula would be used
BTU's/Hr = Overall co-efficient of heat transfer x surface area x TD
Typical U-Factors For Window Construction |
|
Single Pane Window |
1.13 |
Double Pane Window |
0.65 |
Storm Window |
0.45 |
The above factors will change if indoor or outdoor shading is used or if heat absorbing gas is used |
|
How to Reduce Solar Gains through Glass |
Type |
%reduction in Solar Gains |
Heat absorbing Glass |
25% |
Double Pane Glass |
10 to 20% |
Stained Glass |
30 to 65% |
Outside Awnings |
75% |
Outside Venetian Blinds |
35% |
How to Reduce Conduction Gains Through Windows |
Type |
% Reduction in Conduction Gains |
Storm Windows |
60% |
Double Pane Windows |
43% |
Transmission/ Window Gain Calculation
-Find the total heat gain through a residential wall with the following dimensions:
-Length = 20'
-Height = 8'
-Outside ambient temp 85ºF
-Inside room temp 75ºF
-There are two windows located on this wall 2' x 4' ordinary glass no shading
-U-Factor = 0.25 for transmission gain on walls
-U-Factor = 1.13 for transmission gain on windows
Heat Gain Wall= |
Area x |
TD x |
U-Factor |
400 BTU/H= |
(20x8)160 x |
10 x |
0.25 |
Heat Gain Window= |
Area x |
TD x |
U-Factor |
180 BTU/H= |
(2x8x2)16 x |
10 x |
1.13 |
Outside Heat Sources (Solar + Conduction Gains)
Floors
Normally floors would be considered to be a heat loss for heating load calculations if it is a slab or basement construction. However if a unconditioned space is located below the floor level which is conditioned it would be calculated in a cooling load calculation
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